override question

[dsdsdsdsd]

hello;

I am learning how to extend my own custom classes;

for instance I have:

// class A
public function a_method() : void
{ trace( "hello class A , a_method");
}



// class B extends A
override public function a_method()
{ trace( "hello class B , a_method");
}


it works fine;

QUESTION: how can I make the class B method override BUT YET ALSO call the class A method?

thus the output should be:
hello class B , a_method
hello class A , a_method



thanks,
Shannon

[CyanBlue]

Maybe you just need to call super(); inside your function to execute what's in Class A???

[Mazoonist]

override public function a_method() {
trace("hello class B , a_method");
super.a_method();
}
BTW, "super()" would call the constructor of A

[dsdsdsdsd]

interesting, it works ... I have to ask then: how can super be a method and a class??

super() AND super....()




thanks,
Shannon

[wvxvw]

super isn't actually a method, it's a directive / keyword, whatever definition you like the best. When it's super() it executes the constructor of the superclass, if it's super.someMethod it executes the someMethod of the superclass.
Imagine you'd need (theoretically) to instantiate the class from within constructor, not calling new MyClass(), than, it would look like "this()", so, super replaces "this" of the superclass.